What is the physical CCD size per frame quality?

[Christopher Lowden]

Hello
Does anyone know what the theoretical "physical" size of a scarlet CCD when using the different frame sizes (4K, 3K, 2K etc)? The reason why I ask is that when doing 3D camera tracking in post, I need to know the physical size of the CCD in comparison to lens length. As the different frame sizes are a zoom on the CCD, i do not get right camera calculation if I use the full frame size. I presume that if I use 36x18.95mm as full frame in 4K on a Scarlett , at 2K the crop equals a frame size of 18x 9.475mm.
I hope this makes sense.
Thanks for any thoughts.

 

[Ulf Krentz]

Sensor size (recordable area):
EPIC/SCARLET: 27.65mm x 14.58

@Resolution
EPIC: 5120x2700

Cheers, Ulf

 

[Dr. Sassi]

What Ulf Krentz said )
From red.com: LENS COVERAGE: 27.7mm (h) x 14.6mm (v) x 31.4 mm (d)
The FF35 in the link below is a DSLR FF, I assume as comparison.

http://www.reduser.net/forum/showthread.php?77349-Epic-M-and-X-Data-Sheet

Make certain that the communication was clear about 4K, 4K WS or 4K HD, etc., for example. (That sounds maybe as nit-picking as to point out that the RED has no CCD, it is a CMOS. Sorry if I went too far with that)

I hope the information in the LINK will clear your question, and some math is perhaps needed to translate this into "mm". Good luck with the project

 

[Brian Merlen]

Most cameras these days use CMOS not CCD. Though there still is a sensor, and with these crop ins you do use less of it, everything else is accurate


Please note a Scarlet in 4k or 4kHD is not the full sensor. The MX in DSMC is a 5k sensor. Scarlet just can't do it at speed so no one shoots it besides on Epic or Dragons... (or time-lapse)

 

[Muhamad Taufiq]

Here's the dimension (h x v (in mm)):

5K FF: 27,648 x 14,58
4K: 22,118 x 11,664
4K HD: 20,736 x 11,664
3K: 16,589 x 8,748
3K HD: 15,552 x 8,748
2K: 11,059 x 5,832
2K HD: 10,368 x 5,832
2K WS: 11,059 x 4,612
1K HD: 6,912 x 3,888
1K WS: 6,912 x 2,592

 

[Christopher Lowden]

Thank you for the reponses. I am now getting accurate camera calculations.
Thanks for all the info.