Daniel Browning
Well-known member
Thanks again. Do you consider resolution to be a part of "signal"? So that a four-fold reduction in resolution, though it reduces noise by half (depending on the resampling algorithm), reduces the resolution four-fold, so there is less noise but also less "signal"? If yes, then I agree, although I haven't heard of that definition of SNR before. If no, and it has nothing to do with what you're saying, then I'm afraid I still don't understand. 