Daniel Browning
Well-known member
Why does a larger sensor with equally large sensor sites demonstrate more DR than a smaller sensor?
Because is has more light from more area and less noise from scaling pixels for spatial frequency.
Compare RED ONE at 2K vs RED ONE at 4K. You should be able to find others on the forum here that will tell you the same thing, but here's the math:
When both are at the same field of view and T/stop: for every pixel in that gets 50,000 photons in 2K mode, the 4K has four pixels. When the 4K is resampled back down to 2K, it results in 200,000 photons, because signal adds linearly.
If the read noise of each 2K pixel is 11 electrons, then the four pixels in 4K mode will have 44 electrons read noise... *but* read noise adds in quadrature, so 4K mode actually results in only 22 electrons [sqrt(11^2 * (4K/2K)^2)] in the final 2K output.
So RED ONE in 4K mode has one stop more dynamic range than RED ONE in 2K mode.
I would think the reduced heat, cross talk etc etc etc would all contribute to a considerably cleaner signal on the smaller sensor with equal sized sensor wells.
Read noise is an important factor, and perhaps that's what you meant, but thermal noise (heat) is not a factor at room temperature and normal shutter speeds (1/48); electronic cross talk, too, is not a factor at 3+ µm pixel sizes, for any size sensor.