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  • Hey all, just changed over the backend after 15 years I figured time to give it a bit of an update, its probably gonna be a bit weird for most of you and i am sure there is a few bugs to work out but it should kinda work the same as before... hopefully :)

Update Red.com

Stefan Christou

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Now that the M-X is shipping as standard, why not update Red.com to reflect this in the tech specs regarding the RED One? M-X is not even mentioned on the tech specs page.

On a side note. Does anyone know the ratio of exposure stops to decibels of DR? i.e. how many decibels would 18 stops be?

PEACE! :coolgleamA:
 
dB = 10 x log10(v1/V2) = 10 x log10 (2^18/1) = 10 x log10 (262144) = 54.185...dB
 
I've read that some german and japanese guys got 170dB and more then 200dB dynamic range image cmos capture with a with a few time exposures. Which should have more then 28-stops.

I think that your math is not right. RED One Mysterium™ has around 66dB and Mysterium-X™ has more then that.

As far as I know Sony EX-1 has 54dB...

Maybe I am wrong...There are different methods for measuring?

I think that 3dB is a 1/2-stop...


66dB/6dB= 11-stops...?
 
I've read that some german and japanese guys got 170dB and more then 200dB dynamic range image cmos capture with a with a few time exposures. Which should have more then 28-stops.

I think that your math is not right. RED One Mysterium™ has around 66dB and Mysterium-X™ has more then that.

As far as I know Sony EX-1 has 54dB...

Maybe I am wrong...There are different methods for measuring?

I think that 3dB is a 1/2-stop...


66dB/6dB= 11-stops...?

You're right. :mad2: The 20-log formula should be used to compare noise resulting from quantization levels:

10 x log10(a^2/b^2) = 20 x log10(a/b)

so

DRdB = 20 x log10(2^18) = 108dB
 
I thought it was just 1 stop = 6dB, since every time you raise a signal 6dB you double the level?

Because brightness level is proportional to square of the quantization level, we need to use 20-log rule, rather than 10-log rule. So, you are right, 1 stop is ratio of 6dB in brightness, not 3dB as, for example, in cases where you may measure the intensity ratio. I know, confusing...:)
 
just a stupid question..
does makes any relationship to audio depth.. as far as I know 1 bit = 6dB of amplitude..

correct, but the sound power ratio would be 3dB if it doubled, where as the sound ratio would be 6dB if amplitude doubled.

edit: sorry for drifting miles away from the actual subject, but the trip seems interesting :)
 
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